Debugger activation detected JS-0005
Bug risk
7 months ago
—
8 months old
Unexpected 'debugger' statement.
65async function postMsg() {
66 if((Date.now() - last_called_postMsg) < 100) {
67 createModal("slow down there")
68 debugger; 69 return;
70 }
71 last_called_postMsg = Date.now()Unexpected 'debugger' statement.
70 function postMsg() {
71 if((Date.now() - last_called_postMsg) < 100) {
72 createModal("slow down there")
73 debugger; 74 return;
75 }
76 last_called_postMsg = Date.now()
Description
The debugger statement is used to tell the JavaScript environment to stop execution and start up a debugger at the current point in the code.
Production code should not contain debugger statements, as they will cause the browser to stop executing code and open the console debugger.
Bad Practice
function isTruthy(x) {
debugger;
return Boolean(x);
}
Recommended
function isTruthy(x) {
return Boolean(x);
}